2h^2-20h+14=0

Solution for 2h^2-20h+14=0 equation:

2h^2-20h+14=0

a = 2; b = -20; c = +14;
Δ = b2-4ac
Δ = -202-4·2·14
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-12\sqrt{2}}{2*2}=\frac{20-12\sqrt{2}}{4}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+12\sqrt{2}}{2*2}=\frac{20+12\sqrt{2}}{4}
$